Let:
- \( a = \) number of children who took exactly 1 ride
- \( b = \) number of children who took exactly 2 rides
- \( c = \) number of children who took all 3 rides = 20
- Total number of children = 85
- Total money collected = 145 (each ride costs Re.1)
Also, it's given that 55 children took at least 2 rides, i.e.,
\[
b + c = 55 b = 55 - 20 = 35
\]
Now total ride revenue:
Each child who took 1 ride paid Re.1 → total from them = \( a \)
Each who took 2 rides paid Rs.2 → total from them = \( 2b = 70 \)
Each who took 3 rides paid Rs.3 → total = \( 3c = 60 \)
Total revenue:
\[
a + 2b + 3c = 145 a + 70 + 60 = 145 a = 15
\]
So, children who took at least one ride:
\[
a + b + c = 15 + 35 + 20 = 70
\]
Children who took no ride:
\[
85 - 70 = \boxed{15}
\]