Step 1: Calculate number of moles of KOH.
\[
n = \frac{\text{Mass of solute}}{\text{Molar mass}} = \frac{28}{56} = 0.5 \, \text{mol}
\]
Step 2: Convert volume of solution into litres.
\[
V = 500 \, \text{mL} = 0.500 \, \text{L}
\]
Step 3: Apply molarity formula.
\[
M = \frac{n}{V} = \frac{0.5}{0.500} = 1.0 \, M
\]
\[
\boxed{\text{Molarity of the solution = 1.0 M}}
\]
0.1 mole of compound S will weigh ...... g, (given the molar mass in g mol\(^{-1}\) C = 12, H = 1, O = 16) 
Among $ 10^{-10} $ g (each) of the following elements, which one will have the highest number of atoms?
Element : Pb, Po, Pr and Pt
The molar mass of the water insoluble product formed from the fusion of chromite ore \(FeCr_2\text{O}_4\) with \(Na_2\text{CO}_3\) in presence of \(O_2\) is ....... g mol\(^{-1}\):