The titration equation for the reaction between dichromate ions (Cr2O72–) and iron ions (Fe2+) in an acidic medium is:
Cr2O72– + 6Fe2+ + 14H+ → 2Cr3+ + 6Fe3+ + 7H2O
The stoichiometry indicates that 1 mole of Cr2O72– oxidizes 6 moles of Fe2+.
Calculate moles of K2Cr2O7:
moles = Molarity × Volume (L) = 0.02 M × 0.020 L = 0.0004 mol
Since 1 mole of Cr2O72– reacts with 6 moles of Fe2+, moles of Fe2+ are:
6 × 0.0004 mol = 0.0024 mol
The molarity of Fe2+ solution is calculated using its volume:
Molarity = (moles/Volume in L) = 0.0024 mol / 0.010 L = 0.24 M
Express it as: 24 × 10–2 M.
The solution value is 24, which lies within the expected range (24,24). Thus, the molarity of the Fe2+ solution is 24×10–2 M.
Applying the law of equivalence,
milliequivalents of Fe2+ = milliequivalents of K2Cr2O7
10 × 1 × M = 20 × 6 × .02
M = 24 × 10–2 M
∴ Answer will be 24.
Calculate the potential for half-cell containing 0.01 M K\(_2\)Cr\(_2\)O\(_7\)(aq), 0.01 M Cr\(^{3+}\)(aq), and 1.0 x 10\(^{-4}\) M H\(^+\)(aq).


Ordinary Differential Equations is an equation that indicates the relation of having one independent variable x, and one dependent variable y, along with some of its other derivatives.
\(F(\frac{dy}{dt},y,t) = 0\)
A partial differential equation is a type, in which the equation carries many unknown variables with their partial derivatives.

It is the linear polynomial equation in which derivatives of different variables exist. Linear Partial Differential Equation derivatives are partial and function is dependent on the variable.

When the degree of f(x,y) and g(x,y) is the same, it is known to be a homogeneous differential equation.
\(\frac{dy}{dx} = \frac{a_1x + b_1y + c_1}{a_2x + b_2y + c_2}\)
Read More: Differential Equations