When all 10 resistors (\( R \)) are connected in series, the maximum resistance is:
\[ R_{\text{max}} = 10R = 10 \times 10 = 100 \, \Omega \]
When all 10 resistors (\( R \)) are connected in parallel, the minimum resistance is:
\[ R_{\text{min}} = \frac{R}{10} = \frac{10}{10} = 1 \, \Omega \]
The ratio is given by:
\[ \frac{R_{\text{max}}}{R_{\text{min}}} = \frac{100}{1} = 100 \]
From the above calculations:
\[ R_{\text{min}} = 1 \, \Omega \]

A wire of resistance $ R $ is bent into a triangular pyramid as shown in the figure, with each segment having the same length. The resistance between points $ A $ and $ B $ is $ \frac{R}{n} $. The value of $ n $ is:

The equivalent resistance between the points \(A\) and \(B\) in the given circuit is \[ \frac{x}{5}\,\Omega. \] Find the value of \(x\). 
Method used for separation of mixture of products (B and C) obtained in the following reaction is: 
In the following \(p\text{–}V\) diagram, the equation of state along the curved path is given by \[ (V-2)^2 = 4ap, \] where \(a\) is a constant. The total work done in the closed path is: 
Let \( ABC \) be a triangle. Consider four points \( p_1, p_2, p_3, p_4 \) on the side \( AB \), five points \( p_5, p_6, p_7, p_8, p_9 \) on the side \( BC \), and four points \( p_{10}, p_{11}, p_{12}, p_{13} \) on the side \( AC \). None of these points is a vertex of the triangle \( ABC \). Then the total number of pentagons that can be formed by taking all the vertices from the points \( p_1, p_2, \ldots, p_{13} \) is ___________.