When all 10 resistors (\( R \)) are connected in series, the maximum resistance is:
\[ R_{\text{max}} = 10R = 10 \times 10 = 100 \, \Omega \]
When all 10 resistors (\( R \)) are connected in parallel, the minimum resistance is:
\[ R_{\text{min}} = \frac{R}{10} = \frac{10}{10} = 1 \, \Omega \]
The ratio is given by:
\[ \frac{R_{\text{max}}}{R_{\text{min}}} = \frac{100}{1} = 100 \]
From the above calculations:
\[ R_{\text{min}} = 1 \, \Omega \]
A wire of resistance $ R $ is bent into a triangular pyramid as shown in the figure, with each segment having the same length. The resistance between points $ A $ and $ B $ is $ \frac{R}{n} $. The value of $ n $ is:

