List of top Physics Questions on Simple Harmonic Motion

One bar magnet is in simple harmonic motion with time period T T in an earth’s magnetic field. If its mass is increased by 9 times, the time period becomes:
Two simple harmonic motions are represented by y1=5[sin⁡2πt+3cos⁡2πt]y_1 = 5 \left[ \sin 2\pi t + \sqrt{3} \cos 2\pi t \right] and y2=5sin⁡[2πt+π4]y_2 = 5 \sin \left[ 2\pi t + \frac{\pi}{4} \right] . The ratio of their amplitudes is:
A body is executing simple harmonic motion. At a displacement x x , its potential energy is E1 E_1 , and at a displacement y y , its potential energy is E2 E_2 . The potential energy E E at a displacement (x+y) (x + y) is:

Distinguish between an ammeter and a voltmeter. (Two points each).
The displacement of a particle performing simple harmonic motion is 13 \frac{1}{3} of its amplitude. What fraction of total energy is its kinetic energy?
 

Obtain the differential equation of linear simple harmonic motion.

The velocity of the bob of a second’s pendulum when it is 6 cm from its mean position and amplitude of 10 cm is:
If two simple harmonic motions having angular frequency 440 rad/s and 396 rad/s are superimposed, what will be the number of beats produced?
The Lissajous figure of two rectangular SHMs of equal frequency and phase difference of π/2 is
If a, b, c, d are in Harmonic progression then
(A) a+d>b+c
(B) a+c=b+d
(C) ad > bc
(D) an +cn>26n
(E) a+d<b+c
Choose the correct answer from the options given below :
A body oscillate with SHM according to equation (SI unit),
x=10cos(2πt+π/4)x= 10cos (2πt+π/4)
at t= 1.5 s, calculate the speed of the body.
A tube closed at one end containing air is excited. It produces the fundamental note of frequency 512 Hz. If the same tube is open at both the ends, the fundamental frequency that can be produced is
The time period of a simple pendulum on a freely moving artificial satellite is
A particle executes linear simple harmonic motion with an amplitude of 3 cm. When the particle is at 2 cm from the mean position, the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is