Question

A particle executes linear simple harmonic motion with an amplitude of 3 cm. When the particle is at 2 cm from the mean position, the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is

• A. \(\frac {\sqrt 5}{\pi}\)
• B. \(\frac {\sqrt 5}{2\pi}\)
• C. \(\frac {4\pi}{\sqrt 5}\)
• D. \(\frac {2\pi}{\sqrt 3}\)

Answer 1

The Correct Option is C

The correct option is (C): \(\frac {4\pi}{\sqrt 5}\).