On the basis of information available for the reaction
\[
\frac{4}{3}\,\text{Al} + \text{O}_2 \rightarrow \frac{2}{3}\,\text{Al}_2\text{O}_3,
\quad \Delta G = -827\,\text{kJ mol}^{-1}\ \text{of } \text{O}_2,
\]
the minimum emf required to carry out electrolysis of \(\text{Al}_2\text{O}_3\) is:
(Given \(1\,F = 96500\,\text{C}\))