Step 1: Recall the formula for electric potential of a charged sphere.
For a conducting sphere:
\[
V = \frac{kQ}{R}
\]
where \(k\) is a constant and \(R\) is the radius of the sphere.
Step 2: Compare the given spheres.
The spheres are identical, so their radii are the same.
Hence, electric potential depends only on the charge.
Step 3: Compare the charges.
\[
Q_A = -5\,\text{C}, \quad Q_B = -16\,\text{C}
\]
Since:
\[
-5>-16
\]
\(-5\,\text{C}\) corresponds to a higher (less negative) potential.
Step 4: Final conclusion.
The sphere carrying charge \(-5\,\text{C}\) is at a higher potential.
\[
\boxed{\text{(A)}}
\]