A solution which is $10^{ - 3 } $ M each in $ Mn^2, \, Fe^{ 2 + }, \, Zn^{ 2 + } $ and $ Hg^{ 2 + } $ is treated with $ 10^{ - 1 6 } M \, sulphide \, ion, $ If $ K_{ sp } $ of $MnS, FeS, ZnS$ and $ HgS $ are $ 10^{ - 15 }, \, 10^{ - 13 }, \, 10^{ - 20} \, and \, 10^{ - 34 } $ respectively, which one will precipitate first?