Question:
A solution of a metal ion when treated with $KI$ gives a red precipitate which dissolves in excess $KI$ to give a colourless solution. Moreover, the solution of metal ion on treatment with a solution of cobalt (II) thiocyanate gives rise to a deep blue crystalline precipitate. The metal ion is
A solution of a metal ion when treated with $KI$ gives a red precipitate which dissolves in excess $KI$ to give a colourless solution. Moreover, the solution of metal ion on treatment with a solution of cobalt (II) thiocyanate gives rise to a deep blue crystalline precipitate. The metal ion is
Updated On: Jun 14, 2022
- $Pb^{2+}$
- $Hg^{2+}$
- $Cu^{2+}$
- $Co^{2+}$
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The Correct Option is B
Solution and Explanation
$ \, \, \, \, \, \, \, Hg^{2+} + 2I^- \longrightarrow HgI_2 \, (red)$
$ \, \, \, \, \, \, \, HgI_2 + 2KI \longrightarrow K_2 [HgI_4]$
$ \, \, \, Hg^{2+} + Co (SCN)_2 \longrightarrow \underset{Blue}{ Co [Hg (SCN)_4]}$
$ \, \, \, \, \, \, \, HgI_2 + 2KI \longrightarrow K_2 [HgI_4]$
$ \, \, \, Hg^{2+} + Co (SCN)_2 \longrightarrow \underset{Blue}{ Co [Hg (SCN)_4]}$
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The d-block elements are placed in groups 3-12 and F-block elements with 4f and 5f orbital filled progressively. The general electronic configuration of d block elements and f- block elements are (n-1) d 1-10 ns 1-2 and (n-2) f 1-14 (n-1) d1 ns2 respectively. They are commonly known as transition elements because they exhibit multiple oxidation states because of the d-d transition which is possible by the availability of vacant d orbitals in these elements.
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