The reaction
${B(OH)_3 + NaOH <=> Na[B(OH)_4]}$
$ { B(OH)_3 + NaOH <=> NaBO_2 + 2 \, H_2O}$
can be made to proceed to forward direction by the addition of
- borax
- cis-l, 2 diol
- trans-1, 2 diol
- ${Na_2HPO_4}$
The Correct Option is B
Solution and Explanation
However, when cis-diol is added to the titration solution, it forms a very stable complex with ${[B(OH)_4]^-}$ formed by the forward reaction, thus effectively removing it from solution. This upsets the balance of the equation and the reaction proceeds completely to the right. Thus all the ${B(OH)_3}$ reacts with NaOH and it acts as a strong acid in the presence of the cis-diol
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Concepts Used:
Group 13 Elements
Group 13 is commonly known as the Boron Family. The boron family comprises:
- Boron (B)
- Aluminum (Al)
- Gallium (Ga)
- Indium (In)
- Thallium (Tl)
Element 113 (Nihonium) gets the name of ununtrium Uut. Each one of the elements has three electrons in the external shell of their nuclear structure is one of the important and mutual properties of the group.
The general electronic configuration for the group 13 elements is ns2 np1.
Density of Boron Family:
Melting point and Boiling Point:
Electronegativity:
Atomic and Ionic Radii:
Compounds of Group 13 Elements:
- Oxides
- Halides
- Borates
- Boron Hydrides
- Diborane
- Borazine