Question:
$CuSO_4$decolourises on addition of KCN, the product is
$CuSO_4$decolourises on addition of KCN, the product is
Updated On: Jun 14, 2022
- $[Cu(CN)_4]^{2-}$
- $Cu^{2+}$ get reduced to form $[Cu(CN)_4]^{3-}$
- $Cu(CN)_2$
- CuCN
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The Correct Option is B
Solution and Explanation
$CuSo_4 + 2KCN \longrightarrow Cu(CN)_2 + K_2 SO_4$
$\underset{Unstable}{2Cu(CN)_2} \longrightarrow2Cu(CN) + \bigg|_{CN}^{CN} \, \, (Cyanogen)$
$CuCN + 3KCN \longrightarrow 3K^+ + [Cu(CN)_4]^{3-}$
$\underset{Unstable}{2Cu(CN)_2} \longrightarrow2Cu(CN) + \bigg|_{CN}^{CN} \, \, (Cyanogen)$
$CuCN + 3KCN \longrightarrow 3K^+ + [Cu(CN)_4]^{3-}$
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