List of top Electrical and Electronic Measurements Questions asked in GATE Electrical Engineering

In the DC-DC converter shown in the figure, the current through the inductor is continuous. The switching frequency is \( 500 \, \text{Hz} \). The voltage (\( V_o \)) across the load is assumed to be constant and ripple-free. The peak inductor current in amperes is (rounded off to the nearest integer).
\includegraphics[width=0.5\linewidth]{64.png}

A single-phase full-controlled thyristor converter bridge is used for regenerative braking of a separately excited DC motor with the following specifications: Rated armature voltage = \( 210 \, \text{V} \), Rated armature current = \( 10 \, \text{A} \), Rated speed = \( 1200 \, \text{rpm} \), Armature resistance = \( 1 \, \Omega \), Input to the converter bridge = \( 240 \, \text{V at 50 Hz} \). Assume that the motor is running at \( 600 \, \text{rpm} \) and the armature terminals of the motor are suitably reversed for regenerative braking. If the armature current of the motor is to be maintained at the rated value, the triggering angle of the converter bridge in degrees should be (rounded off to 2 decimal places).
\begin{tabular}{|l|l|} \hline Parameter & Value
\hline Rated armature voltage & 210 V
\hline Rated armature current & 10 A
\hline Rated speed & 1200 rpm
\hline Armature resistance & 1 $\Omega$
\hline Input to the converter bridge & 240 V at 50 Hz
\hline \end{tabular}
The armature of the DC motor is fed from the fullcontrolled bridge and the field current is kept constant.

Consider the stable closed-loop system shown in the figure. The asymptotic Bode magnitude plot of \( G(s) \) has a constant slope of \( -20 \, \text{dB/decade} \) at least till \( 100 \, \text{rad/sec} \) with the gain crossover frequency being \( 10 \, \text{rad/sec} \). The asymptotic Bode phase plot remains constant at \( -90^\circ \) at least till \( \omega = 10 \, \text{rad/sec} \). The steady-state error of the closed-loop system for a unit ramp input is (rounded off to 2 decimal places).
\includegraphics[width=0.5\linewidth]{58.png}

Consider the stable closed-loop system shown in the figure. The magnitude and phase values of the frequency response of \( G(s) \) are given in the table. The value of the gain \( K_I (> 0) \) for a \( 50^\circ \) phase margin is (rounded off to 2 decimal places).
\begin{tabular}{|c|c|c|} \hline $\omega$ in rad/sec & Magnitude in dB & Phase in degrees
\hline 0.5 & -7 & -40
\hline 1.0 & -10 & -80
\hline 2.0 & -18 & -130
\hline 10.0 & -40 & -200
\hline \end{tabular}
\includegraphics[width=0.5\linewidth]{59.png}

In the given circuit, the diodes are ideal. The current \( I \) through the diode \( D_1 \) in milliamperes is (rounded off to two decimal places).
\includegraphics[width=0.5\linewidth]{60.png}

A difference amplifier is shown in the figure. Assume the op-amp to be ideal. The CMRR (in dB) of the difference amplifier is (rounded off to 2 decimal places).
\includegraphics[width=0.5\linewidth]{61.png}

The single line diagram of a lossless system is shown in the figure. The system is operating in steady-state at a stable equilibrium point with the power output of the generator being \( P_{max} \sin \delta \), where \( \delta \) is the load angle and the mechanical power input is \( 0.5 P_{max} \). A fault occurs on line 2 such that the power output of the generator is less than \( 0.5 P_{max} \) during the fault. After the fault is cleared by opening line 2, the power output of the generator is \( \frac{P_{max}}{\sqrt{2}} \sin \delta \). If the critical fault clearing angle is \( \pi/2 \) radians, the accelerating area on the power angle curve is \_\_\_ times \( P_{max} \) (rounded off to 2 decimal places).
\includegraphics[width=0.5\linewidth]{56.png}

For the three-bus lossless power network shown in the figure, the voltage magnitudes at all the buses are equal to 1 per unit (pu), and the differences of the voltage phase angles are very small. The line reactances are marked in the figure, where $\alpha$, $\beta$, $\gamma$, and $x$ are strictly positive. The bus injections $P_1$ and $P_2$ are in pu. If $P_1 = mP_2$, where $m>0$ and the real power flow from bus 1 to bus 2 is 0 pu, then which one of the following options is correct?
\includegraphics[width=0.5\linewidth]{41.png}

A forced commutated thyristorized step-down chopper is shown. Neglect the ON-state drop across power devices. Assume that the capacitor is initially charged to 50 V with the polarity shown in the figure. The load current \(I_l\) can be assumed to be constant at 10 A. Initially, \(Th_M\) is ON and \(ThA\) is OFFThe turn-off time available to \( T_{H4} \) in microseconds, when \( T_{H4} \) is triggered, is \_\_\_\_\_ (rounded off to the nearest integer).
\includegraphics[width=0.5\linewidth]{35.png}

The table lists two instrument transformers and their features:
\begin{tabular}{|l|l|} \hline Instrument Transformers & Features
\hline X) Current Transformer (CT) & P) Primary is connected in parallel to the grid
& Q) Open circuited secondary is not desirable
& R) Primary current is the line current
\hline Y) Potential Transformer (PT) & S) Secondary burden affects the primary current
\hline \end{tabular}
Which matches are correct?

All the elements in the circuit are ideal. The power delivered by the 10 V source in watts is:
\includegraphics[width=0.5\linewidth]{13.png}