The major product formed in the following reaction is:
The major product formed in the following reaction:
The least acidic among the following compounds:
is:
The reaction of \(NiBr_2\) with two equivalents of \(PPh_3\) in \(CS_2\) at -78°C gives a red-colored diamagnetic complex, \([NiBr_2 \text{(PPh}_3\text{)}_2]\). This transforms to a green-colored paramagnetic complex with the same molecular formula at 25°C. The geometry and the number of unpaired electrons in the green-colored complex, respectively, are:
The rate of the substitution reaction of \([Co(CN)_5Cl]^3\)\(^-\) with OH\(^-\) to give \([Co(CN)_5(OH)]^3\)\(^-\) follows:
The phase diagram of CO\(_2\) is shown below:
Phase diagram of CO\(_2\) with solid, liquid, and gas phases labeled along with critical temperature \(T_c\) and triple point temperature \(T_1\) The correct statement(s) about CO\(_2\) is/are:
The normal mode(s) of vibration of H\(_2\)O is/are:
Among the following eight compounds, the number of compound(s) which can exhibit stereoisomerism is \(\underline{\hspace{2cm}}\).
The number of signal(s) in the \( ^1H \) NMR spectrum of the following compound
recorded at 25°C in \(CDCl_3\) is \(\underline{\hspace{2cm}}\).
The spin-only magnetic moment of \([Co({H}_2\text{O)}_6^{2+}]\) (rounded off to one decimal place) is \(\underline{\hspace{2cm}}\) BM.
The geometry and the number of unpaired electrons in tetrakis(1-norbomyl)Co, respectively, are:
The major product formed in the following reaction
In the following reaction sequence:
The major products P and Q, respectively, are:
Among the following, the compounds which can be prepared by nucleophilic substitution reaction are:
In the following reaction
the major products X and Y, respectively, are:
The major products P and Q formed in the following reactions respectively, are:
The rate constants for the decomposition of a molecule in the presence of oxygen are \(0.237 \times 10^{-4}\) L mol\(^{-1}\) s\(^{-1}\) at 0 °C and \(2.64 \times 10^{-4}\) L mol\(^{-1}\) s\(^{-1}\) at 25 °C. The activation energy for this reaction (rounded off to one decimal place) is \(\underline{\hspace{2cm}}\) kJ mol\(^{-1}\).Given: \( R = 8.314 \, \text{J mol}^{-1} \text{K}^{-1} \).
