In reactions involving n-BuLi, a deprotonation occurs, creating a reactive intermediate that can undergo further reactions, such as nucleophilic attack, resulting in the formation of the desired products.
In this reaction, the lithium reagent (n-BuLi) deprotonates the starting compound, forming an intermediate anion. This intermediate undergoes a reaction with the electrophile (which could be an electrophilic double bond), leading to the formation of X. The subsequent steps with xylene and then HgCl\(_2\), CdCO\(_3\), and H\(_2\)O induce further reactions, with X being transformed into Y. The final product Y involves the formation of an ester group with a phenyl group attached, as shown in the answer.
Step 1: Analyze the reagents.
The use of n-BuLi indicates a deprotonation to form a reactive intermediate. This intermediate then reacts with the electrophile, as seen in the formation of X.
Step 2: Understand the role of xylene and HgCl\(_2\), CdCO\(_3\).
Xylene (in reflux conditions) facilitates the formation of a reactive intermediate, while HgCl\(_2\) and CdCO\(_3\) are used to promote further reactions and functionalize the structure.
Step 3: Consider the final product.
After the transformations, the final product (Y) is expected to be a structure with a phenyl group (Ph) attached to a sulfur atom, and an ester group is also formed, leading to the final structure matching option (C).
Final Answer:
(C) \(\text{S Me} \text{S Ph} \) and \(\text{O Me} \)
