In reactions involving sec-BuLi and ZnCl\(_2\), the organozinc reagent formed is a key intermediate in many coupling reactions, such as those catalyzed by palladium.
In this reaction sequence, the first step involves treating the given compound with sec-BuLi in THF, which results in the formation of an organolithium reagent. This reagent then reacts with \( \text{ZnCl}_2 \) in the second step, leading to the major product P. Finally, the compound undergoes a palladium-catalyzed reaction to form product Q.
After carefully considering the nature of the reactions, we deduce that the major products formed are as follows:
- Product P involves the formation of a zinc halide (\( \text{ZnCl} \)).
- Product Q involves the formation of a nitrogen-containing compound, specifically an arylamine, as a result of the palladium-catalyzed reaction.
Thus, the correct answer is (B) \( \text{ZnCl} \) and \( \text{N} \).
Final Answer:
(B) \( \text{ZnCl} \) and \( \text{N} \).
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