If \(P(B) = \frac{3}{5}\), \(P(A/B) = \frac{1}{2}\), and \(P(A \cup B) = \frac{4}{5}\), then \(P(A \cup B)' + P(A')\) is :
\(\int x^x(1 + \log x) \, dx\), \(\text{ is equal to:}\)
The current passing through the 100\(\Omega\) resistor in the given electrical circuit is:
\( F_A, F_B, \) and \( F_C \) are three forces acting at point \( P \) as shown in the figure. The whole system is in equilibrium state. The magnitude of \( F_A \) is: