Stomach acid, a dilute solution of $HCl$ in water, can be neutralized by reaction with sodium hydrogen carbonate,
$ {NaHCO_3_{(aq)} +HCL_{(aq)} ->NaCL_{(aq)} +H_2O_{(l)} +CO_2_{(g)} }$
How many milliliters of 0.125 M NaHCO solution are needed to neutralize 18.0 mL of 0.100 M HCL?