Question:

CH3COOHLiAlH4A+CH3COOHH3O+B+H2OCH _{3} COOH \xrightarrow{ LiAlH _{4}}A + CH _{3} COOH \xrightarrow{ H _{3} O ^{+}} B + H _{2} O In the above reactions ' AA ' and ' BB ' respectively are

Updated On: Jul 27, 2022
  • CH3COOC2H5,C2H5OHCH_{3}COOC_{2} H_{5},\, C_{2}H_{5}OH
  • CH3CHO,C2H5OHCH_{3}CHO,\,C_{2} H_{5} OH
  • C2H5OH,CH3CHOC_{2}H_{5}OH,\,CH_{3} CHO
  • C2H5OH,CH3COOC2H5C_{2}H_{5}OH,\,CH_{3}COOC_{2} H_{5}
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The Correct Option is D

Solution and Explanation

CH3COOH+4H LiAlH 4CH3CH2OH(A)+H2OCH _{3} COOH +4 H \xrightarrow{\text { LiAlH }_{4}}\underset{(A)}{CH _{3} CH _{2} OH} + H _{2} O CH3CH2OH(A)+CH3COOHH3O+\underset{(A)}{CH _{3} CH _{2} OH} + CH _{3} COOH \stackrel{ H _{3} O ^{+}}{\longrightarrow} CH3COOC2H5(B)+H2O\underset{(B)}{C{H}_{3}COOC_{2} H_{5}}+H_{2}O
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