Question:

$ NaCl $ is less soluble in heavy water than in ordinary water. Dielectric constant of ordinary water is more than that of heavy water.

Updated On: Jul 28, 2022
  • If both Assertion: and Reason: are true and the Reason: is the correct explanation of the Assertion
  • If both Assertion: and Reason: are true but the Reason: is not the correct explanation of the Assertion
  • If Assertion: is true but Reason: is false
  • If both Assertion: and Reason: are false
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The Correct Option is A

Solution and Explanation

$NaCl$ is less soluble in heavy water than in ordinary water because dielectric constant of ordinary water (i.e., $81$ ) is more than that of heavy water (i.e., $80$ ).
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Concepts Used:

Heavy Water

Heavy water (2H2O, D2O - deuterium oxide) is a form of water that consists only of deuterium rather than the common hydrogen-1 isotope that composes most of the hydrogen in normal water. The presence of the heavier hydrogen isotope gives the water distinct nuclear properties, and the increase of mass gives it slightly distinct physical and chemical properties when compared to normal water.

There are some other heavy forms of water such as;

  1. Semiheavy water
  2. Heavy-oxygen water
  3. Tritiated water

Properties of Hard Water:

  1. Heavy water is slighter dissociated than light water at a given temperature, and the true concentration of D+ ions is slighter than  H+ ions would be for a light water sample at the same temperature.
  2. Heavy water is more concentrated than ordinary water, and heavy water has physically distinct properties that can be seen without equipment if a frozen sample is dropped into normal water, as it will sink.