: $p$-dichlorobenzene is less soluble in organic solvents than the corresponding $o$-isomer.
: $o$-dichlorobenzene is polar while $p$-dichlorobenzene is not
If both Assertion: and Reason: are true and the Reason: is the correct explanation of the Assertion
If both Assertion: and Reason: are true but the Reason: is not the correct explanation of the Assertion
If Assertion: is true but Reason: is false
If both Assertion: and Reason: are false
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The Correct Option isB
Solution and Explanation
$p$-dichlorobenzene is more symmetrical than o-isomer, so fits closely in the crystal lattice and hence, greater amount of energy is needed to break the crystal lattice. Thus $p$-isomer is less soluble than o-isomer.
Benzene is a colorless liquid with a distinct odor.
It's highly flammable and volatile.
It is soluble in organic solvents while insoluble in water.
Its boiling point is 80.5°C.
It shows resonance.
Chemical Properties:
Nitration: Nitration involves the reaction when benzene is reacted with nitric acid in the presence of sulphuric acid. The temperature then remains at 55°C and it results in the formation of nitrobenzene.
Sulphonation: Benzene reacts with fuming sulphuric acid and results in the formation of benzene sulfonic acid in sulphonation reactions.
Halogenation: Benzene reacts with halogen in the presence of the Lewis acid resulting in the formation of aryl halide. This reaction is known as halogenation.
Friedel Crafts Acylation reaction: During the reaction of the benzene with an acyl halide, in presence of Lewis acid, it results in the formation of acyl benzene. This is called Friedel craft’s acylation reaction.
Friedel Crafts Alkylation reaction: During the reaction of the benzene with an alkyl halide, in presence of Lewis acid like anhydrous Aluminium Chloride, alkyl benzene is formed. This is called Friedel craft’s alkylation reaction.