\( z_1, z_2, z_3 \) represent the vertices A, B, C of a triangle ABC respectively in the Argand plane. If
\[ |z_1 - z_2| = \sqrt{25 - 12 \sqrt{3}}, \] \[ \left|\frac{z_1 - z_3}{z_2 - z_3}\right| = \frac{3}{4}, \] \[ \text{and } \angle ACB = 30^\circ, \]
Then the area (in sq. units) of that triangle is:
\( z_1, z_2, z_3 \) represent the vertices A, B, C of a triangle ABC respectively in the Argand plane. If
\[ |z_1 - z_2| = \sqrt{25 - 12 \sqrt{3}}, \] \[ \left|\frac{z_1 - z_3}{z_2 - z_3}\right| = \frac{3}{4}, \] \[ \text{and } \angle ACB = 30^\circ, \]
Then the area (in sq. units) of that triangle is:
Show Hint
- $\frac{3}{2}$
- $3$
- $5$
- $\frac{5}{2}$
The Correct Option is B
Solution and Explanation
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