The reaction of lead chromate with NaOH (in hot, excess conditions) results in the formation of a soluble dianionic complex:
PbCrO4 + NaOH (hot, excess) → [Pb(OH)4]2- + Na2CrO4
The product [Pb(OH)4]2- is a dianionic complex with a coordination number of four.
The portion of the line \( 4x + 5y = 20 \) in the first quadrant is trisected by the lines \( L_1 \) and \( L_2 \) passing through the origin. The tangent of an angle between the lines \( L_1 \) and \( L_2 \) is: