The reaction of lead chromate with NaOH (in hot, excess conditions) results in the formation of a soluble dianionic complex:
PbCrO4 + NaOH (hot, excess) → [Pb(OH)4]2- + Na2CrO4
The product [Pb(OH)4]2- is a dianionic complex with a coordination number of four.
Let \( y = f(x) \) be the solution of the differential equation
\[ \frac{dy}{dx} + 3y \tan^2 x + 3y = \sec^2 x \]
such that \( f(0) = \frac{e^3}{3} + 1 \), then \( f\left( \frac{\pi}{4} \right) \) is equal to:
Find the IUPAC name of the compound.
If \( \lim_{x \to 0} \left( \frac{\tan x}{x} \right)^{\frac{1}{x^2}} = p \), then \( 96 \ln p \) is: 32