Question:
\(\frac {x}{2019}+\frac {y}{2020}=2, \frac {2x}{2019}-\frac {y}{2020}=1\), \(∴(x, y)=\)
\(\frac {x}{2019}+\frac {y}{2020}=2, \frac {2x}{2019}-\frac {y}{2020}=1\), \(∴(x, y)=\)
Updated On: Apr 29, 2024
- (2019, 2020)
- (2020, 2019)
- (2019, 2019)
- (2020, 2020)
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The Correct Option is A
Solution and Explanation
The correct option is (A): (2019, 2020).
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