Integrate the function: \(\sqrt{x^2+4x+6}\)
Solution and Explanation
Let \(I=\int \sqrt{x^2+4x+6} \,dx\)
=\(\int \sqrt{x^2+4x+4+2} \,dx\)
=\(\int \sqrt{x^2+4x+4+2} \,dx\)
=\(\int \sqrt{(x+2)^2+(\sqrt2)^2}dx\)
=It is known that,\(\int \sqrt{x^2+a^2}dx=\frac{x}{2}\sqrt{x^2+a^2}+\frac{a^2}{2}\log\mid x+\sqrt{x^2+a^2 }\mid+C\)
∴\(I = \frac{(x+2)}{2}\sqrt{x^2+4x+6}+\frac{2}{2}\log \mid(x+2)+\sqrt{x^2+4x+6}\mid+C\)
=\(\frac{(x+2)}{2}\sqrt{x^2+4x+6}+\log \mid (X+2)+\sqrt{x^2+4x+6}\mid+C\)
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Concepts Used:
Integrals of Some Particular Functions
There are many important integration formulas which are applied to integrate many other standard integrals. In this article, we will take a look at the integrals of these particular functions and see how they are used in several other standard integrals.
Integrals of Some Particular Functions:
- ∫1/(x2 – a2) dx = (1/2a) log|(x – a)/(x + a)| + C
- ∫1/(a2 – x2) dx = (1/2a) log|(a + x)/(a – x)| + C
- ∫1/(x2 + a2) dx = (1/a) tan-1(x/a) + C
- ∫1/√(x2 – a2) dx = log|x + √(x2 – a2)| + C
- ∫1/√(a2 – x2) dx = sin-1(x/a) + C
- ∫1/√(x2 + a2) dx = log|x + √(x2 + a2)| + C
These are tabulated below along with the meaning of each part.
