\(∫\frac {x-1}{\sqrt {x^2-1}}\ dx\) = \(∫\frac {x}{\sqrt {x^2-1}}\ dx\) - \(∫\frac {1}{\sqrt {x^2-1}}\ dx\) ……....(1)
\(For ∫\frac {x}{\sqrt {x^2-1}} dx, \ let x^2-1 = t ⇒ 2x dx = dt\)
\(∴ ∫\frac {x}{\sqrt {x^2-1}} dx = \frac 12 ∫\frac {dt}{\sqrt t}\)
\(=\frac 12 ∫t^{-\frac 12} dt\)
\(=\frac 12[2t^{\frac 12}]\)
\(=\sqrt t\)
\(=\sqrt {x^2-1}\)
\(From\ (1), we\ obtain\)
\(∫\frac {x-1}{\sqrt {x^2-1}}\ dx\) = \(∫\frac {x}{\sqrt {x^2-1}}\ dx\) - \(∫\frac {1}{\sqrt {x^2-1}}\ dx\) \([∫\frac {1}{\sqrt {x^2-a^2}} \ dt = log\ |x+\sqrt {x^2-a^2|}]\)
\(= \sqrt {x^2-1}-log|x+\sqrt {x^2-1}|+C\)
What is the Planning Process?
There are many important integration formulas which are applied to integrate many other standard integrals. In this article, we will take a look at the integrals of these particular functions and see how they are used in several other standard integrals.
These are tabulated below along with the meaning of each part.