Write two different vectors having the same direction.
Consider \(\overrightarrow p=(\hat i+\hat j+\hat k)\) and \(\overrightarrow q=(2\hat i+2\hat j+2\hat k)\).
The direction cosines of \(\overrightarrow p\) are given by,
\(I=\frac{1}{\sqrt{1^2+1^2+1^2}}=\frac{1}{\sqrt 3}\), \(m=\frac{1}{\sqrt{1^2+1^2+1^2}}=\frac{1}{\sqrt 3}\), and \(n=\frac{1}{\sqrt{1^2+1^2+1^2}}=\frac{1}{\sqrt 3}\).
The direction cosines of \(\overrightarrow q\) are given by
\(I=\frac{2}{\sqrt{2^2+2^2+2^2}}=\frac{2}{2\sqrt3}\frac{1}{\sqrt 3}\), \(m=\frac{2}{\sqrt{2^2+2^2+2^2}}=\frac{2}{2\sqrt3}\frac{1}{\sqrt 3}\), and \(n=\frac{2}{\sqrt{2^2+2^2+2^2}}=\frac{2}{2\sqrt3}\frac{1}{\sqrt 3}\).
The direction cosines of \(\overrightarrow p\) and \(\overrightarrow q\) are the same. Hence, the two vectors have the same direction.
A compound (A) with molecular formula $C_4H_9I$ which is a primary alkyl halide, reacts with alcoholic KOH to give compound (B). Compound (B) reacts with HI to give (C) which is an isomer of (A). When (A) reacts with Na metal in the presence of dry ether, it gives a compound (D), C8H18, which is different from the compound formed when n-butyl iodide reacts with sodium. Write the structures of A, (B), (C) and (D) when (A) reacts with alcoholic KOH.
When a vector is multiplied by a scalar quantity, the magnitude of the vector changes in proportion to the scalar magnitude, but the direction of the vector remains the same.
In contrast, the scalar has only magnitude, and the vectors have both magnitude and direction. To determine the magnitude of a vector, we must first find the length of the vector. The magnitude of a vector formula denoted as 'v', is used to compute the length of a given vector ‘v’. So, in essence, this variable is the distance between the vector's initial point and to the endpoint.