Step 1: Write the given equation.
\[
2y = 10 - y^2
\]
Step 2: Bring all terms to one side.
\[
y^2 + 2y - 10 = 0
\]
Step 3: Compare with the standard quadratic form.
The standard quadratic equation is
\[
ax^2 + bx + c = 0
\]
By comparison, we get
\[
a = 1, \quad b = 2, \quad c = -10
\]
Step 4: Conclusion.
Hence, the equation in standard form is \(y^2 + 2y - 10 = 0\) with
\[
a = 1, \; b = 2, \; c = -10
\]
Final Answer:
\[
\boxed{a = 1, \; b = 2, \; c = -10}
\]