Substituting n = 1, 2, 3, 4, 5, we obtain
a1 = 2×1-\(\frac{3}{6} =\frac{-1}{6}\)
a2 = 2×2-\(\frac{3}{6} = \frac{1}{6}\)
a3 = 2×3-\(\frac{3}{6} = \frac{3}{6} = \frac{1}{2}\)
a4 = 2×4-\(\frac{3}{6} = \frac{5}{6}\)
a5 = 2×5-\(\frac{3}{6} = \frac{7}{6}\)
Therefore, the required terms are \(\frac{-1}{6}, \frac{1}{6},\frac{1}{2}, \frac{5}{6}, and \frac{7}{6}\)
Find the mean and variance for the following frequency distribution.
Classes | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 |
Frequencies | 5 | 8 | 15 | 16 | 6 |