Question:
Write the first five terms of each of the sequences in Exercises 1 to 6 whose nth terms are: an = 2n.
Write the first five terms of each of the sequences in Exercises 1 to 6 whose nth terms are: an = 2n.
Updated On: Jan 27, 2026
Hide Solution
Verified By Collegedunia
Solution and Explanation
an = 2n
Substituting n = 1, 2, 3, 4, 5, we obtain
a1 = 21 = 2
a2 = 22 = 4
a3 = 23 = 8
a4 = 24 = 16
a5 = 25 = 32
Therefore, the required terms are 2, 4, 8, 16, and 32.
Was this answer helpful?
0
0
Top Questions on Sequences and Series
- The value of \[ \sum_{k=1}^{\infty} (-1)^{k+1}\left(\frac{k(k+1)}{k!}\right) \] is:
- JEE Main - 2026
- Mathematics
- Sequences and Series
- Let the area of the region bounded by the curve \( y = \max \{ \sin x, \cos x \} \), lines \( x = 0 \), \( x = 3\pi/2 \), and the x-axis be A. Then, \( A + A^2 \) is equal to :
- JEE Main - 2026
- Mathematics
- Sequences and Series
- Among the statements :
I: If the given determinants are equal, then \( \cos^2\alpha + \cos^2\beta + \cos^2\gamma = \frac{3}{2} \), and
II: If the polynomial determinant equals \( px + q \), then \( p^2 = 196q^2 \), identify the truth value.- JEE Main - 2026
- Mathematics
- Sequences and Series
- In a G.P., if the product of the first three terms is \(27\) and the set of all possible values for the sum of its first three terms is \( \mathbb{R} - (a,b) \), then \( a^2+b^2 \) is equal to:
- JEE Main - 2026
- Mathematics
- Sequences and Series
- Let \(729, 81, 9, 1, \ldots\) be a sequence and \(P_n\) denote the product of the first \(n\) terms of this sequence. If \[ 2 \sum_{n=1}^{40} (P_n)^{\frac{1}{n}} = \frac{3^{\alpha} - 1}{3^{\beta}} \] and \(\gcd(\alpha, \beta) = 1\), then \(\alpha + \beta\) is equal to
- JEE Main - 2026
- Mathematics
- Sequences and Series
View More Questions
Questions Asked in CBSE Class XI exam
- Balance the following redox reactions by ion-electron method:
(a)MnO4- (aq) + I - (aq) → MnO2(s) + I2(s) (in basic medium)
(b) MnO4- (aq) + SO2(g) → Mn2+(aq) +HSO4- (aq) (in acidic solution)
(c) H2O2(aq)+Fe2+(aq) → Fe3+ (aq) + H2O (l) (in acidic solution)
(d) Cr2O72-+ SO2(g) → Cr3+ (aq) +SO42- (aq) (in acidic solution)- CBSE Class XI
- Oxidation Number
- Write the resonance structures for SO3 , NO2 and NO3-
- CBSE Class XI
- Kossel-Lewis Approach to Chemical Bonding
- At 700 K, equilibrium constant for the reaction:
\(H_2 (g) + I_2 (g) ⇋ 2HI (g)\)
is 54.8. If 0.5 mol L–1 of HI(g) is present at equilibrium at 700 K, what are the concentration of H2(g) and I2(g) assuming that we initially started with HI(g) and allowed it to reach equilibrium at 700 K?- CBSE Class XI
- Law Of Chemical Equilibrium And Equilibrium Constant
- Find the mean deviation about the mean for the data 4, 7, 8, 9, 10, 12, 13, 17.
- CBSE Class XI
- Statistics
Find the mean deviation about the mean for the data 38, 70, 48, 40, 42, 55, 63, 46, 54, 44.
- CBSE Class XI
- Statistics
View More Questions