Question:
Write the first five terms of each of the sequences in Exercises 1 to 6 whose nth terms are: an = n (n + 2).
Write the first five terms of each of the sequences in Exercises 1 to 6 whose nth terms are: an = n (n + 2).
Updated On: Oct 18, 2023
Hide Solution
Verified By Collegedunia
Solution and Explanation
an = n(n+2)
Substituting n = 1, 2, 3, 4, and 5, we obtain
a1= 1(1+2)=3
a2= 2(2+2)=8
a3= 3(3+2)=15
a4= 4(4+2)=24
a5= 5(5+2)=35
Therefore, the required terms are 3, 8, 15, 24, and 35.
Was this answer helpful?
0
0
Top Questions on Sequences and Series
- Let $ x_1, x_2, x_3, x_4 $ be in a geometric progression. If 2, 7, 9, 5 are subtracted respectively from $ x_1, x_2, x_3, x_4 $, then the resulting numbers are in an arithmetic progression. Then the value of $ \frac{1}{24} (x_1 x_2 x_3 x_4) $ is:
- JEE Main - 2025
- Mathematics
- Sequences and Series
If $ \frac{1}{1^4} + \frac{1}{2^4} + \frac{1}{3^4} + ... \infty = \frac{\pi^4}{90}, $ $ \frac{1}{1^4} + \frac{1}{3^4} + \frac{1}{5^4} + ... \infty = \alpha, $ $ \frac{1}{2^4} + \frac{1}{4^4} + \frac{1}{6^4} + ... \infty = \beta, $ then $ \frac{\alpha}{\beta} $ is equal to:
- JEE Main - 2025
- Mathematics
- Sequences and Series
The sum $ 1 + \frac{1 + 3}{2!} + \frac{1 + 3 + 5}{3!} + \frac{1 + 3 + 5 + 7}{4!} + ... $ upto $ \infty $ terms, is equal to
- JEE Main - 2025
- Mathematics
- Sequences and Series
- Let $ a_1, a_2, a_3, ... $ be a G.P. of increasing positive numbers. If $ a_3 a_5 = 729 $ and $ a_2 + a_4 = \frac{111}{4} $, then $ 24(a_1 + a_2 + a_3) $ is equal to
- JEE Main - 2025
- Mathematics
- Sequences and Series
- The sum 1 + 3 + 11 + 25 + 45 + 71 + ... upto 20 terms, is equal to
- JEE Main - 2025
- Mathematics
- Sequences and Series
View More Questions
Questions Asked in CBSE Class XI exam
- Take one flower of the family Solanaceae and write its semi-technical description. Also draw their floral diagram.
- CBSE Class XI
- The Flower
- \(\text{tan x}=-\frac{4}{3},\text{x\, in\, quadrant \,II.}\)
- CBSE Class XI
- Trigonometric Functions of Sum and Difference of Two Angles
- Find \((x + 1)^6 - (x - 1)^6\). Hence or otherwise evaluate \((\sqrt2 + 1)^6 + (\sqrt2 - 1)^6.\)
- CBSE Class XI
- Binomial Theorem for Positive Integral Indices
- Find \((a + b)^4 - (a - b)^4\). Hence, evaluate \((\sqrt3 + \sqrt2)^4 - (\sqrt3 - \sqrt2)^4\).
- CBSE Class XI
- Binomial Theorem for Positive Integral Indices
- Find the derivative of
(i) 2x - \(\frac{3}{4}\)
(ii)(5x3+3x-1)(x-1)
(iii) x-3(5+3x) (iv)x5(3-6x-9)
(v) x-4(3-4x-5) (vi)\(\frac{2}{x+1}-\frac{x^2}{3x-1}\)- CBSE Class XI
- Derivatives
View More Questions