When preparing Mohr’s salt, \(\text{H}_2\text{SO}_4\) is added for the following reasons:
Step 1: Understanding the role of \(\text{H}_2\text{SO}_4\)
Ferrous sulphate is prone to hydrolysis in aqueous solutions, especially when exposed to atmospheric oxygen. The hydrolysis leads to the formation of ferric hydroxide, which can contaminate the Mohr’s salt crystals.
Adding dilute sulphuric acid prevents the hydrolysis of ferrous sulphate by maintaining an acidic medium, which stabilizes the ferrous ions and prevents oxidation or decomposition.
Step 2: Reason for not choosing other options
Option (2): Ammonium sulphate does not hydrolyze under normal conditions, so preventing its hydrolysis is irrelevant.
Option (3): Although adding \(\text{H}_2\text{SO}_4\) makes the medium acidic, the main purpose is to prevent hydrolysis.
Option (4): The rate of formation of crystals is not directly influenced by \(\text{H}_2\text{SO}_4\) but rather by cooling and saturation.
Conclusion:
The correct reason for adding \(\text{H}_2\text{SO}_4\) is to prevent the hydrolysis of ferrous sulphate.
Consider the following sequence of reactions : 
Molar mass of the product formed (A) is ______ g mol\(^{-1}\).
Predict the major product $ P $ in the following sequence of reactions:
(i) HBr, benzoyl peroxide
(ii) KCN
(iii) Na(Hg), $C_{2}H_{5}OH$
If the system of equations \[ (\lambda - 1)x + (\lambda - 4)y + \lambda z = 5 \] \[ \lambda x + (\lambda - 1)y + (\lambda - 4)z = 7 \] \[ (\lambda + 1)x + (\lambda + 2)y - (\lambda + 2)z = 9 \] has infinitely many solutions, then \( \lambda^2 + \lambda \) is equal to:
The output of the circuit is low (zero) for:

(A) \( X = 0, Y = 0 \)
(B) \( X = 0, Y = 1 \)
(C) \( X = 1, Y = 0 \)
(D) \( X = 1, Y = 1 \)
Choose the correct answer from the options given below:
The metal ions that have the calculated spin only magnetic moment value of 4.9 B.M. are
A. $ Cr^{2+} $
B. $ Fe^{2+} $
C. $ Fe^{3+} $
D. $ Co^{2+} $
E. $ Mn^{2+} $
Choose the correct answer from the options given below
Which of the following circuits has the same output as that of the given circuit?
