For an arithmetic progression (A.P.), the \(n\)-th term is given by:
\[
T_n = a + (n - 1) \times d
\]
where \(a\) is the first term and \(d\) is the common difference. In this case, \(a = 20\) and \(d = -2\). We are given that the \(n\)-th term is \(-80\). Thus, we have:
\[
-80 = 20 + (n - 1)(-2)
\]
\[
-80 = 20 - 2(n - 1)
\]
\[
-80 - 20 = -2(n - 1)
\]
\[
-100 = -2(n - 1)
\]
\[
50 = n - 1
\]
\[
n = 51
\]
Thus, the correct answer is option (2).