Step 1: Understanding the Reaction
The reaction of a phenol with phthalic anhydride in the presence of concentrated sulfuric acid is the phthalein dye test. This reaction forms a phthalein dye, which is typically colored. The reaction is an electrophilic aromatic substitution where two molecules of phenol react with one molecule of phthalic anhydride.
Step 2: Mechanism of the Phthalein Dye Test
In this reaction, the electrophile (a carbocation generated from phthalic anhydride and conc. H\(_2\)SO\(_4\)) attacks the phenol ring. For the reaction to proceed and form the characteristic dye structure, the \textit{para} position (with respect to the -OH group) on the phenol ring must be unsubstituted (i.e., must have a hydrogen atom). The substitution occurs at this para position.
Step 3: Analyzing the Options
(A) Phenol: The para position is free. It will react to form phenolphthalein, which is a well-known indicator.
(B) Catechol (1,2-dihydroxybenzene): The para position with respect to one -OH group (C4) is free. It will give a positive test.
(C) Resorcinol (1,3-dihydroxybenzene): The para position with respect to one -OH group (C4) is free and highly activated. It will react readily to form fluorescein.
(D) p-Cresol (4-methylphenol): In this molecule, the para position with respect to the -OH group is already occupied by a methyl (-CH\(_3\)) group. Since there is no hydrogen atom at the para position, the electrophilic substitution required to form the phthalein dye cannot occur.
Step 4: Final Answer
Therefore, p-cresol does not give colour with phthalic anhydride because its para position is blocked.