Statement-I : $\text{KMnO}_4 \xrightarrow{\Delta} \text{NH}_2$ followed by $\text{Br}_2/\text{KOH} \rightarrow \text{NH}_2$. Statement-II : $\text{CH}_3\text{NH}_2 \xrightarrow{(i) \text{ Br}_2/\text{H}_2\text{O}, (ii) \text{ NaNO}_2/\text{HCl}, (iii) \text{ H}_3\text{PO}_2/\Delta} \text{CH}_3\text{Br}$.
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Hofmann Bromamide Degradation ($\text{Br}_2/\text{KOH}$) converts primary amides to primary amines, losing one carbon atom. Diazotization of $1^\circ$ aliphatic amines leads to rapid decomposition, generally not yielding stable products.
Statement I:
Step 1: Hofmann bromamide reaction converts primary amide to primary amine with loss of one carbon atom:
\[
R-CONH_2 \xrightarrow{Br_2/KOH} R-NH_2
\]
Step 2: The reaction sequence shown leads to formation of amine. Hence Statement I is correct.
Statement II:
Step 3: Diazotization of primary amine using $NaNO_2/HCl$ forms diazonium salt.
Step 4: Treatment with $H_3PO_2$ reduces diazonium group to hydrogen.
Step 5: Thus, conversion shown is chemically valid.
Hence, both statements are correct.
