Step 1: Recall the mass conservation equation.
The principle of mass conservation states that the rate of change of mass within a control volume must be equal to the net flux of mass through the control surface. Mathematically, this is expressed as: \[ \frac{\partial}{\partial t} \iiint_V \rho \, dV + \iint_S \rho \vec{v} \cdot \vec{n} \, ds = 0, \] where: - \( \rho \) is the density, - \( \vec{v} \) is the velocity vector, - \( \vec{n} \) is the outward unit normal vector on the surface \( S \), - \( V \) is the control volume.
Step 2: Simplify the equation.
Rewriting the mass conservation equation: \[ -\frac{\partial}{\partial t} \iiint_V \rho \, dV = \iint_S \rho \vec{v} \cdot \vec{n} \, ds. \] This matches Option (C).
Step 3: Analyze other options.
Option (A): Incorrect, as it describes a volumetric flux without accounting for mass conservation.
Option (B): Incorrect, as it only considers the temporal change of mass in the volume and neglects surface flux.
Option (D): Incorrect, as it misrepresents the derivative form of the conservation equation.
Conclusion: The mass conservation equation is \( -\frac{\partial}{\partial t} \iiint_V \rho \, dV = \iint_S \rho \vec{v} \cdot \vec{n} \, ds \).
A steel deck plate of a tanker is supported by two longitudinal stiffeners as shown in the figure. The width of the plate is \( a \) and its length is 5 times the width. Assume that the long edge is simply supported, and the short edge is free. The plate is loaded by a distributed pressure, \( p = p_0 \sin\left(\frac{\pi y}{a}\right) \), where \( p_0 \) is the pressure at \( y = a/2 \). The flexural rigidity of the plate is \( D \). The plate equation is given by
Consider the matrices
\( M = \begin{pmatrix}
2 & 1 \\
0 & 2
\end{pmatrix} \)
\( N = \begin{pmatrix}
1 & 0 & 0 \\
1 & 2 & 0 \\
1 & 1 & 0
\end{pmatrix} \)
Which one of the following is true?
A ship with a standard right-handed coordinate system has positive \(x\), \(y\), and \(z\) axes respectively pointing towards bow, starboard, and down as shown in the figure. If the ship takes a starboard turn, then the drift angle, sway velocity, and the heel angle of the ship for a steady yaw rate respectively are:
A closed system is undergoing a reversible process 1–P–2 from state 1 to 2, as shown in the figure, where X and Y are thermodynamic properties. An irreversible process 2–Q–1 brings the system back from 2 to 1. The net change in entropy of the system and surroundings during the above-mentioned cycle are _______ respectively.
A ship of 3300 tonne displacement is undergoing an inclining experiment in seawater of density 1025 kg/m\(^3\). A mass of 6 tonne is displaced transversely by 12 m as shown in the figure. This results in a 0.12 m deflection of a 11 m long pendulum suspended from the centerline. The transverse metacenter of the ship is located at 7.25 m above the keel.
The distance of the center of gravity from the keel is ________ m (rounded off to two decimal places).
A multi-cell midship section of a ship with \( B = 40 \, {m} \) and \( D = 20 \, {m} \) is shown in the figure. The shear-flows are given as \( q_1 = q_2 = q_3 = 0.9376 \, {MN/m} \). The applied twisting moment on the midship section is ___________ MN·m (rounded off to two decimal places).
Consider a weightless, frictionless piston with a 2 kg mass placed on it as shown in the figure. At equilibrium in position 1, the cylinder contains 0.1 kg of air. The piston cross-sectional area is 0.01 m2. The ambient pressure in the surroundings outside the piston-cylinder arrangement is 0 bar (absolute). When the mass above the piston is removed instantaneously, it moves up and hits the stop at position 2, which is 0.1 m above the initial position.
Assuming \( g = 9.81 \, {m/s}^2 \), the thermodynamic work done by the system during this process is ________ J (answer in integer).