The paramagnetic behaviour depends on the number of unpaired electrons. Using the electronic configurations:
\(Complex\) | \(\text{Number of unpaired electrons}\) | \(\mu = \sqrt{n(n+2)}\) B.M. |
---|---|---|
\([\text{Co(H}_2\text{O)}_6]^{2+}\) | 3 | 3.87 |
\([\text{Fe(H}_2\text{O)}_6]^{2+}\) | 4 | 4.89 |
\([\text{Mn(H}_2\text{O)}_6]^{2+}\) | 5 | 5.92 |
\([\text{Cr(H}_2\text{O)}_6]^{2+}\) | 4 | 4.89 |
The least paramagnetic complex is \([\text{Co(H}_2\text{O)}_6]^{2+}\), as it has the fewest unpaired electrons (3).
Write two consequences of lanthanide contraction.
Which is the correct IUPAC name for
The steam volatile compounds among the following are:
If the system of equations \[ x + 2y - 3z = 2, \quad 2x + \lambda y + 5z = 5, \quad 14x + 3y + \mu z = 33 \] has infinitely many solutions, then \( \lambda + \mu \) is equal to:}
The equilibrium constant for decomposition of $ H_2O $ (g) $ H_2O(g) \rightleftharpoons H_2(g) + \frac{1}{2} O_2(g) \quad (\Delta G^\circ = 92.34 \, \text{kJ mol}^{-1}) $ is $ 8.0 \times 10^{-3} $ at 2300 K and total pressure at equilibrium is 1 bar. Under this condition, the degree of dissociation ($ \alpha $) of water is _____ $\times 10^{-2}$ (nearest integer value). [Assume $ \alpha $ is negligible with respect to 1]