Question:

Which one of the following complexes will exhibit the least paramagnetic behaviour ? [Atomic number, Cr = 24, Mn = 25, Fe = 26, Co = 27]

Updated On: Nov 21, 2024
  • [Co(H2O)6]+2
  • [Fe(H2O)6]+2
  • [Mn(H2O)6]+2
  • [Cr(H2O)6]+2
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The Correct Option is A

Solution and Explanation

The paramagnetic behaviour depends on the number of unpaired electrons. Using the electronic configurations:

\(Complex\)\(\text{Number of unpaired electrons}\)\(\mu = \sqrt{n(n+2)}\) B.M.
\([\text{Co(H}_2\text{O)}_6]^{2+}\)33.87
\([\text{Fe(H}_2\text{O)}_6]^{2+}\)44.89
\([\text{Mn(H}_2\text{O)}_6]^{2+}\)55.92
\([\text{Cr(H}_2\text{O)}_6]^{2+}\)44.89

The least paramagnetic complex is \([\text{Co(H}_2\text{O)}_6]^{2+}\), as it has the fewest unpaired electrons (3).

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