1. Probability density: - The probability density of finding the electron is maximum at the nucleus.
2. Distance from the nucleus: - The electron can be found at a distance $2 \mathrm{a}_{0}$ from the nucleus.
3. Spherical symmetry: - The 1s orbital is spherically symmetrical.
4. Total energy: - The total energy of the electron is maximum when it is at a distance $\mathrm{a}_{0}$ from the nucleus.
This statement is incorrect. Therefore, the correct answer is (4).
Match the following:
Which of the following is the correct electronic configuration for \( \text{Oxygen (O)} \)?
Let $ P_n = \alpha^n + \beta^n $, $ n \in \mathbb{N} $. If $ P_{10} = 123,\ P_9 = 76,\ P_8 = 47 $ and $ P_1 = 1 $, then the quadratic equation having roots $ \alpha $ and $ \frac{1}{\beta} $ is: