1. Probability density: - The probability density of finding the electron is maximum at the nucleus.
2. Distance from the nucleus: - The electron can be found at a distance $2 \mathrm{a}_{0}$ from the nucleus.
3. Spherical symmetry: - The 1s orbital is spherically symmetrical.
4. Total energy: - The total energy of the electron is maximum when it is at a distance $\mathrm{a}_{0}$ from the nucleus.
This statement is incorrect. Therefore, the correct answer is (4).
Match the following:
Which of the following is the correct electronic configuration for \( \text{Oxygen (O)} \)?
Let \[ I(x) = \int \frac{dx}{(x-11)^{\frac{11}{13}} (x+15)^{\frac{15}{13}}} \] If \[ I(37) - I(24) = \frac{1}{4} \left( b^{\frac{1}{13}} - c^{\frac{1}{13}} \right) \] where \( b, c \in \mathbb{N} \), then \[ 3(b + c) \] is equal to:
For the thermal decomposition of \( N_2O_5(g) \) at constant volume, the following table can be formed, for the reaction mentioned below: \[ 2 N_2O_5(g) \rightarrow 2 N_2O_4(g) + O_2(g) \] Given: Rate constant for the reaction is \( 4.606 \times 10^{-2} \text{ s}^{-1} \).