Question:
Which of the following sets of elements is not correctly arranged according to the given property?
Which of the following sets of elements is not correctly arranged according to the given property?
Show Hint
Remember, metallic nature increases as you move down a group and decreases across a period.
Updated On: Mar 24, 2025
- \( S>Se>O \) (Electron gain enthalpy)
- \( F>O>Cl \) (Electronegativity)
- \( Na>Li>Al \) (Metallic radius)
- \( Na>K>Ba \) (Metallic nature)
Hide Solution
Verified By Collegedunia
The Correct Option is D
Solution and Explanation
Step 1: Understanding Periodic Trends
1. Electron Gain Enthalpy:
The correct trend follows \( S>Se>O \), as oxygen has a lower electron gain enthalpy due to its small size and electron repulsion.
2. Electronegativity:
Fluorine has the highest electronegativity, followed by oxygen and chlorine, making \( F>O>Cl \) a correct order.
3. Metallic Radius:
Across a period, metallic radius decreases, while down a group, it increases. The given order \( Na>Li>Al \) is incorrect since aluminum is a metalloid and has a much smaller atomic radius than sodium and lithium.
4. Metallic Nature:
Metallic nature increases down the group. The correct order should be \( Ba>K>Na \), not \( Na>K>Ba \).
Thus, the incorrect arrangement is option (4) \( Na>K>Ba \).
Was this answer helpful?
0
0
Top Questions on Periodic Table
- Correct order of first ionisation energy of B, In, Ga, and Al is:
- UPCATET - 2025
- Chemistry
- Periodic Table
- Incorrect match of IUPAC symbol of elements with its respective atomic number is:
- UPCATET - 2025
- Chemistry
- Periodic Table
- The energy of second Bohr orbit of hydrogen atom is \(-3.4 \, \text{eV}\). The energy of the fourth Bohr orbit of the He\(^+\) ion will be
- AP EAPCET - 2025
- Chemistry
- Periodic Table
- a, b, c, d are electromagnetic radiations. Frequencies of a, b, c are $3 \times 10^{15$ Hz, respectively, whereas the wavelength of c, d are 400 nm, 750 nm, respectively. The increasing order of their energies is}
- AP EAPCET - 2025
- Chemistry
- Periodic Table
- The radius of fourth orbit in \( He^+ \) ion is \( R_1 \) pm and radius of third orbit in \( Li^{2+} \) ion is \( R_2 \) pm. The value of \( (R_1 - R_2) \) in pm is:
- AP EAPCET - 2025
- Chemistry
- Periodic Table
View More Questions
Questions Asked in AP EAMCET exam
- In a meter bridge experiment, a resistance of 9 Ω is connected in the left gap and an unknown resistance greater than 9 Ω is connected in the right gap. If the resistance in the gaps are interchanged, the balancing point shifts by 10 cm. The unknown resistance is:
- AP EAMCET - 2024
- Wheatstone Bridge
- The angle made by the resultant vector of two vectors \( 2\hat{i} + 3\hat{j} + 4\hat{k} \) and \( 2\hat{i} - 7\hat{j} - 4\hat{k} \) with the x-axis is:
- If the longest wavelength of the spectral line of the Paschen series of \( \text{Li}^{2+} \) ion spectrum is \( x \) Å, then the longest wavelength (in Å) of the Lyman series of the hydrogen spectrum is:
- AP EAMCET - 2024
- Atomic Spectra
- Let \( A(2, 3), B(1, -1) \) be two points. If \( P \) is a variable point such that \( \angle APB = 90^\circ \), then the locus of \( P \) is
- AP EAMCET - 2024
- solution of system of linear inequalities in two variables
- The charge \( q \) (in coulombs) passing through a \( 10 \Omega \) resistor as a function of time \( t \) (in seconds) is given by: \[ q = 3t^2 - 2t + 6 \] The potential difference across the ends of the resistor at time \( t = 5 \) s is:
- AP EAMCET - 2024
- coulombs law
View More Questions