Match the LIST-I with LIST-II.
| LIST-I | LIST-II | ||
|---|---|---|---|
| A. | Pnicogen (group 15) | I. | Ts | 
| B. | Chalcogen (group 16) | II. | Og | 
| C. | Halogen (group 17) | III. | Lv | 
| D. | Noble gas (group 18) | IV. | Mc | 
Choose the correct answer from the options given below :

Let's match the families of elements with their corresponding symbols from the given lists, focusing on the most recently named elements in these groups:
A. Pnicogen (group 15): The elements in Group 15 are Nitrogen (N), Phosphorus (P), Arsenic (As), Antimony (Sb), Bismuth (Bi), and Moscovium (Mc). Therefore, Pnicogen matches with Mc. A - IV
B. Chalcogen (group 16): The elements in Group 16 are Oxygen (O), Sulfur (S), Selenium (Se), Tellurium (Te), Polonium (Po), and Livermorium (Lv). Therefore, Chalcogen matches with Lv. B - III
C. Halogen (group 17): The elements in Group 17 are Fluorine (F), Chlorine (Cl), Bromine (Br), Iodine (I), Astatine (At), and Tennessine (Ts). Therefore, Halogen matches with Ts. C - I
D. Noble gas (group 18): The elements in Group 18 are Helium (He), Neon (Ne), Argon (Ar), Krypton (Kr), Xenon (Xe), Radon (Rn), and Oganesson (Og). Therefore, Noble gas matches with Og. D - II
The correct matching is A-IV, B-III, C-I, D-II, which corresponds to option (2).
Match List-I with List-II 
Choose the correct answer from the options given below:
Let \( y^2 = 12x \) be the parabola and \( S \) its focus. Let \( PQ \) be a focal chord of the parabola such that \( (SP)(SQ) = \frac{147}{4} \). Let \( C \) be the circle described by taking \( PQ \) as a diameter. If the equation of the circle \( C \) is: \[ 64x^2 + 64y^2 - \alpha x - 64\sqrt{3}y = \beta, \] then \( \beta - \alpha \) is equal to:
Let one focus of the hyperbola $ \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 $ be at $ (\sqrt{10}, 0) $, and the corresponding directrix be $ x = \frac{\sqrt{10}}{2} $. If $ e $ and $ l $ are the eccentricity and the latus rectum respectively, then $ 9(e^2 + l) $ is equal to:
Let $ A \in \mathbb{R} $ be a matrix of order 3x3 such that $$ \det(A) = -4 \quad \text{and} \quad A + I = \left[ \begin{array}{ccc} 1 & 1 & 1 \\2 & 0 & 1 \\4 & 1 & 2 \end{array} \right] $$ where $ I $ is the identity matrix of order 3. If $ \det( (A + I) \cdot \text{adj}(A + I)) $ is $ 2^m $, then $ m $ is equal to: