Match the LIST-I with LIST-II.
| LIST-I | LIST-II | ||
| A. | Pnicogen (group 15) | I. | Ts |
| B. | Chalcogen (group 16) | II. | Og |
| C. | Halogen (group 17) | III. | Lv |
| D. | Noble gas (group 18) | IV. | Mc |
Choose the correct answer from the options given below :
To solve this matching problem, we need to align each group from LIST-I with its respective element from LIST-II. Let's break it down:
Now, let's match them with LIST-II:
Thus, the correct answer is: A-IV, B-III, C-I, D-II
Let's match the families of elements with their corresponding symbols from the given lists, focusing on the most recently named elements in these groups:
A. Pnicogen (group 15): The elements in Group 15 are Nitrogen (N), Phosphorus (P), Arsenic (As), Antimony (Sb), Bismuth (Bi), and Moscovium (Mc). Therefore, Pnicogen matches with Mc. A - IV
B. Chalcogen (group 16): The elements in Group 16 are Oxygen (O), Sulfur (S), Selenium (Se), Tellurium (Te), Polonium (Po), and Livermorium (Lv). Therefore, Chalcogen matches with Lv. B - III
C. Halogen (group 17): The elements in Group 17 are Fluorine (F), Chlorine (Cl), Bromine (Br), Iodine (I), Astatine (At), and Tennessine (Ts). Therefore, Halogen matches with Ts. C - I
D. Noble gas (group 18): The elements in Group 18 are Helium (He), Neon (Ne), Argon (Ar), Krypton (Kr), Xenon (Xe), Radon (Rn), and Oganesson (Og). Therefore, Noble gas matches with Og. D - II
The correct matching is A-IV, B-III, C-I, D-II, which corresponds to option (2).

The correct sequence of reagents for the above conversion of X to Y is :
Match List-I with List-II 
Choose the correct answer from the options given below:

Two circular discs of radius \(10\) cm each are joined at their centres by a rod, as shown in the figure. The length of the rod is \(30\) cm and its mass is \(600\) g. The mass of each disc is also \(600\) g. If the applied torque between the two discs is \(43\times10^{-7}\) dyne·cm, then the angular acceleration of the system about the given axis \(AB\) is ________ rad s\(^{-2}\).
