The major products obtained from the reactions in List-II are the reactants for the named reactions mentioned in List-I. Match each entry in List-I with the appropriate entry in List-II and choose the correct option. 
P → 5; Q → 4; R → 2; S → 1
(P) Stephen reaction:
Stephen reaction reduces nitriles (RCN) to aldehydes. The precursor is usually benzonitrile, which is derived from benzoic acid.
\[ \Rightarrow P \rightarrow \boxed{2} \quad \text{(Benzoic acid)} \] (Q) Sandmeyer reaction:
Used to substitute an amino group on an aromatic ring (from aniline) via diazotization. Requires a nitro compound as a precursor.
\[ \Rightarrow Q \rightarrow \boxed{3} \quad \text{(Nitrobenzene)} \] (R) Hoffmann bromamide degradation reaction:
Converts amides to amines with one fewer carbon. The amine product is Toluene.
\[ \Rightarrow R \rightarrow \boxed{4} \quad \text{(Toluene)} \] (S) Cannizzaro reaction:
Occurs with aldehydes having no alpha-H (like benzaldehyde), which can be derived from oxidation of toluene.
\[ \Rightarrow S \rightarrow \boxed{1} \quad \text{(Toluene)} \]
Final Answer: \( \boxed{\text{B}} \)


Let $ P(x_1, y_1) $ and $ Q(x_2, y_2) $ be two distinct points on the ellipse $$ \frac{x^2}{9} + \frac{y^2}{4} = 1 $$ such that $ y_1 > 0 $, and $ y_2 > 0 $. Let $ C $ denote the circle $ x^2 + y^2 = 9 $, and $ M $ be the point $ (3, 0) $. Suppose the line $ x = x_1 $ intersects $ C $ at $ R $, and the line $ x = x_2 $ intersects $ C $ at $ S $, such that the $ y $-coordinates of $ R $ and $ S $ are positive. Let $ \angle ROM = \frac{\pi}{6} $ and $ \angle SOM = \frac{\pi}{3} $, where $ O $ denotes the origin $ (0, 0) $. Let $ |XY| $ denote the length of the line segment $ XY $. Then which of the following statements is (are) TRUE?