Let's analyze each oxidation reaction:
A. $I^- \rightarrow I_2$:
Both $K_2Cr_2O_7$ and $KMnO_4$ can oxidize iodide to iodine in acidic medium.
This reaction is possible with both oxidizing agents.
B. $S^{2-} \rightarrow S$:
Both $K_2Cr_2O_7$ and $KMnO_4$ can oxidize sulfide to sulfur in acidic medium.
This reaction is possible with both oxidizing agents.
C. $Fe^{2+} \rightarrow Fe^{3+}$:
Both $K_2Cr_2O_7$ and $KMnO_4$ can oxidize $Fe^{2+}$ to $Fe^{3+}$ in acidic medium.
This reaction is possible with both oxidizing agents.
D. $I^- \rightarrow IO_3^-$:
Both $K_2Cr_2O_7$ and $KMnO_4$ can oxidize iodide to iodate in acidic medium, but it requires a stronger oxidizing power.
This reaction is possible under strong conditions, but not always consistent in standard acidic conditions.
E. $S_2O_3^{2-} \rightarrow SO_4^{2-}$:
Thiosulfate oxidation to sulfate is more complex and specific to certain oxidizing power and conditions. $KMnO_4$ typically does not oxidize thiosulfate to sulfate quantitatively in acidic medium, while $K_2Cr_2O_7$ may do so under vigorous conditions.
This reaction is not consistently carried out by both oxidizing agents.
Therefore, reactions A, B, and C are the only ones that are consistently carried out by both $K_2Cr_2O_7$ and $KMnO_4$ under standard acidic conditions.
Final Answer:
The final answer is $ (3)\ A,\ B\ \text{and}\ C\ \text{only} $.
$\mathrm{KMnO}_{4}$ acts as an oxidising agent in acidic medium. ' X ' is the difference between the oxidation states of Mn in reactant and product. ' Y ' is the number of ' d ' electrons present in the brown red precipitate formed at the end of the acetate ion test with neutral ferric chloride. The value of $\mathrm{X}+\mathrm{Y}$ is _______ .
Given below are two statements:
Statement (I): The first ionization energy of Pb is greater than that of Sn.
Statement (II): The first ionization energy of Ge is greater than that of Si.
In light of the above statements, choose the correct answer from the options given below:
