Question:

Which of the following numbers are not perfect cubes: 
  1. 216 
  2. 128 
  3.  1000 
  4.  100 
  5.  46656

Updated On: Nov 30, 2023
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Solution and Explanation

(i) 216216
Factorization of 216
Prime factors of 216=2 ×2 ×2 ×3 ×3 ×3216 = 2 × 2 × 2 × 3 × 3 × 3
Here all factors are in groups of 33’s (in triplets)
Therefore, 216216 is a perfect cube number.


(ii) 128128
Factorization of 128
Prime factors of 128=2×2 ×2 ×2×2 ×2×2128 = 2× 2 × 2 × 2× 2 × 2× 2
Here one factor 22 does not appear in a 33’s group
Therefore, 128128 is not a perfect cube.


(iii) 10001000
Factorization of 1000
Prime factors of 1000=2×2×2×5×5×51000 = 2\times2\times2\times5\times5\times5
Here all factors appear in 33’s group.
Therefore, 10001000 is a perfect cube.


(iv) 100100
Factorization of 100
Prime factors of 100=2×2×5×5 100 = 2 \times 2 \times 5 \times 5
Here all factors do not appear in 33’s group.
Therefore, 100100 is not a perfect cube.


(v) 4665646656
Factorization of 46656
Prime factors of 46656=2×2×2×2×2×2×3×3×3×3×3×346656 =2 \times2\times2\times2\times2\times2\times3\times3\times3\times3\times3\times3
Here all factors appear in 33’s group.
Therefore, 4665646656 is a perfect cube.

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