Step 1: Understanding the Concept:
A polynomial is an algebraic expression in which the variables involved have only non-negative integer powers. The coefficients can be any real number.
Step 2: Detailed Explanation:
Let's analyze each option:
(A) \(x^2 - 7\): The powers of x are 2 and 0 (since \(7 = 7x^0\)). Both are non-negative integers. So, this is a polynomial.
(B) \(2x^2 + 7x + 6\): The powers of x are 2, 1, and 0. All are non-negative integers. So, this is a polynomial.
(C) \(\frac{1}{2}x^2 + \frac{1}{2}x + 4\): The powers of x are 2, 1, and 0. All are non-negative integers. The coefficients (\(\frac{1}{2}, \frac{1}{2}, 4\)) are real numbers. So, this is a polynomial.
(D) \(x + \frac{4}{x}\): This expression can be rewritten using exponents as \(x^1 + 4x^{-1}\). The power of x in the second term is -1, which is a negative integer. According to the definition of a polynomial, the powers of the variable must be non-negative. Therefore, this expression is not a polynomial.
Step 3: Final Answer:
The expression \(x + \frac{4}{x}\) is not a polynomial because it contains a term with a negative exponent. This matches option (D).
Let \( M \) be a \( 7 \times 7 \) matrix with entries in \( \mathbb{R} \) and having the characteristic polynomial \[ c_M(x) = (x - 1)^\alpha (x - 2)^\beta (x - 3)^2, \] where \( \alpha>\beta \). Let \( {rank}(M - I_7) = {rank}(M - 2I_7) = {rank}(M - 3I_7) = 5 \), where \( I_7 \) is the \( 7 \times 7 \) identity matrix.
If \( m_M(x) \) is the minimal polynomial of \( M \), then \( m_M(5) \) is equal to __________ (in integer).
In the given figure, graph of polynomial \(p(x)\) is shown. Number of zeroes of \(p(x)\) is
