Question:

Find the zeroes of the polynomial: \[ q(x) = 8x^2 - 2x - 3 \] Hence, find a polynomial whose zeroes are 2 less than the zeroes of \(q(x)\)

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Use quadratic formula and transformation of zeroes formula for new polynomials.
Updated On: May 20, 2025
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Solution and Explanation

Use quadratic formula: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] Find zeroes \(\alpha, \beta\) Then, new zeroes: \[ \alpha-2, \ \beta-2 \] Form new polynomial: If sum = \(S'\), product = \(P'\) Use: \[ S' = (\alpha-2) + (\beta-2) \] \[ P' = (\alpha-2)(\beta-2) \] Then, polynomial: \[ x^2 - (S')x + P' \]
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