The solubility product, $K_{sp}$, is the product of the concentrations of the ions in their dissolved state, each raised to the power of its respective coefficient in the dissociation equation. For copper(II) hydroxide, Cu(OH)$_2$, the dissociation is given by:
\[
{Cu(OH)}_2 \rightleftharpoons {Cu}^{2+} + 2 {OH}^-
\]
Thus, the expression for the solubility product is:
\[
K_{sp} = [{Cu}^{2+}][{OH}^-]^2
\]
Hence, the correct answer is (a).