The acceleration due to gravity at a height \( h \) above the Earth's surface is: \[ g' = \frac{GM}{(R + h)^2}. \] Using the binomial expansion for \( (1 + \frac{h}{R})^2 \), neglecting higher-order terms: \[ \frac{1}{(1 + \frac{h}{R})^2} \approx 1 - \frac{2h}{R}. \] Substituting this approximation: \[ g' = \frac{GM}{R^2} \left( 1 - \frac{2h}{R} \right). \] Since \( g = \frac{GM}{R^2} \), we can write: \[ g' = g \left( 1 - \frac{2h}{R} \right). \]
Final Answer: The acceleration due to gravity is: \[ \boxed{g' = g \left( 1 - \frac{2h}{R} \right)}. \]
If $ \lim_{x \to 0} \left( \frac{\tan x}{x} \right)^{\frac{1}{x^2}} = p $, then $ 96 \log_e p $ is equal to _______
In mechanics, the universal force of attraction acting between all matter is known as Gravity, also called gravitation, . It is the weakest known force in nature.
According to Newton’s law of gravitation, “Every particle in the universe attracts every other particle with a force whose magnitude is,
On combining equations (1) and (2) we get,
F ∝ M1M2/r2
F = G × [M1M2]/r2 . . . . (7)
Or, f(r) = GM1M2/r2
The dimension formula of G is [M-1L3T-2].