The silver mirror test is a chemical test used to identify aldehydes. Aldehydes, when treated with ammoniacal silver nitrate (Tollens’ reagent), reduce silver ions to metallic silver, forming a mirror-like deposit.
- Formic acid (A) is an aldehyde and will react with Tollens’ reagent.
- Formaldehyde (B) is also an aldehyde and will give a positive silver mirror test.
- Benzaldehyde (C) is another aldehyde and will also give a positive silver mirror test.
- Acetone (D) is a ketone and does not reduce Tollens’ reagent, so it will not give a silver mirror.
Thus, the correct answer is (2), A, B, and C only.
Convert Ethanal to But-2-enal
If all the words with or without meaning made using all the letters of the word "KANPUR" are arranged as in a dictionary, then the word at 440th position in this arrangement is:
If the system of equations \[ x + 2y - 3z = 2, \quad 2x + \lambda y + 5z = 5, \quad 14x + 3y + \mu z = 33 \] has infinitely many solutions, then \( \lambda + \mu \) is equal to:}
The equilibrium constant for decomposition of $ H_2O $ (g) $ H_2O(g) \rightleftharpoons H_2(g) + \frac{1}{2} O_2(g) \quad (\Delta G^\circ = 92.34 \, \text{kJ mol}^{-1}) $ is $ 8.0 \times 10^{-3} $ at 2300 K and total pressure at equilibrium is 1 bar. Under this condition, the degree of dissociation ($ \alpha $) of water is _____ $\times 10^{-2}$ (nearest integer value). [Assume $ \alpha $ is negligible with respect to 1]