Step 1: Understand the concept of the degree of reduction.
The degree of reduction per carbon-mole refers to the number of electrons a molecule has gained or lost relative to its oxidized form. A more reduced molecule has a higher number of electrons associated with it. In organic compounds, this is often linked to the number of hydrogen atoms bonded to carbon and the absence of oxygen bonds.
Step 2: Analyze each option.
Glucose (A): A six-carbon carbohydrate containing multiple hydroxyl groups and one aldehyde group. Despite being a carbohydrate, its overall oxidation state is moderate.
Lactic acid (B): Contains a hydroxyl group and a carboxylic acid group. It is partially oxidized but still retains some reducing power.
Acetic acid (C): A two-carbon molecule with a methyl group and a carboxylic acid group. Each carbon's oxidation state is fairly similar to those in lactic acid, making their reduction degrees comparable.
Formic acid (D): The simplest carboxylic acid with one carbon. This carbon is highly oxidized due to its bonding to two oxygen atoms, making its degree of reduction significantly lower.
Step 3: Conclusion.
Glucose, lactic acid, and acetic acid share a similar degree of reduction per carbon-mole. Formic acid is more oxidized and does not match the others in reduction degree.
Final Answer:
The correct answer is \( \boxed{(A), (B), (C)} \).