Let the second side be \(a^4\) units
Let the third side be \(6x\) units.
Given that,
\(a^4 \times 6 = 6^x\)
or, \(a^4 = 6^{x-1}\)
Total perimeter \((P) \) = \(7776 + a^4 + 6^x = 7776 + 6^{x-1} + 6^x = 7776 + 6^{x-1} \times 7\)
\(\Rightarrow p- 7776 = 6^{x-1} \times 7\)
From the given options, only \(16848 - 7776\) is divisible by \(7\).
Hence, option A is the correct answer.
When $10^{100}$ is divided by 7, the remainder is ?